Re-evaluating the Graphs
Graph 1 Analysis:
Let’s identify the axes and the processes based on the positions of states 1, 2, and 3 shown in the diagram.
- Axes: For the diagonal line to represent an Isobaric process ($V \propto T$) and the vertical line to represent an Isothermal process ($T = \text{const}$), we must have Horizontal Axis $A = T$ (Temperature) and Vertical Axis $B = V$ (Volume).
- Process $1 \to 2$: The line connects state 1 (bottom-right) to state 2 (top-right). This is a vertical line, meaning Temperature ($A$) is constant while Volume ($B$) changes. This is an Isothermal process.
- Process $2 \to 3$: The line connects state 2 (top-right) to state 3 (bottom-left). This line passes through the origin, implying $V \propto T$. This is an Isobaric process (Pressure is constant).
Graph 2 Analysis:
This is a Pressure ($P$) vs Volume ($B=V$) graph.
- Curve between $z$ and $y$: Represents an Isothermal process ($PV = \text{const}$).
- Horizontal line between $x$ and $y$: Represents an Isobaric process ($P = \text{const}$).
Mapping the States
We need to match the sequence of processes: Isothermal $\to$ Isobaric.
- Step 1 ($1 \to 2$): Isothermal. In Graph 2, the Isothermal path is the curve connecting $z$ and $y$. So, states 1 and 2 correspond to $z$ and $y$.
- Step 2 ($2 \to 3$): Isobaric. From state 2, we must go to state 3 via an isobaric path (horizontal line). In Graph 2, the horizontal line connects $y$ and $x$. This implies state 2 must be $y$ to allow the transition. Consequently, state 3 is $x$.
Conclusion:
- State $1 = z$
- State $2 = y$ (The common state between Isothermal and Isobaric paths)
- State $3 = x$
Therefore: $x=3, y=2, z=1$.
Correct Option: (c) $A=T, B=V, x=3, y=2, z=1$