THERMAL O21

Solution Q21

Analysis

The process described is the expansion of an ideal gas into a vacuum (evacuated part B). This is known as Free Expansion.

Thermodynamics of Free Expansion

  • Work Done ($W$): Since the gas expands against a vacuum ($P_{ext} = 0$), the work done is zero ($W = \int P_{ext} dV = 0$).
  • Heat Transfer ($Q$): The vessel is perfectly heat insulating, so $Q = 0$.
  • Internal Energy ($\Delta U$): According to the First Law of Thermodynamics, $\Delta U = Q – W = 0 – 0 = 0$.

For an ideal gas, internal energy depends only on temperature ($U \propto T$). Since $\Delta U = 0$, the temperature change $\Delta T = 0$.

This holds true for both the first opening (partial expansion) and the second opening (full expansion), as the system is isolated throughout.

Correct Option: (d) During both the first and the second openings, the temperature remains constant.