Solution: Question 8
For the toy to be self-righting, its Center of Mass (COM) must be lower than the center of curvature of the base. The base is the lower sphere (radius 9 cm), so the critical height is y = 9 cm.
yCOM < 9
Positions (height y): Load M at 0, Lower mass m2 at 9, Upper mass m1 at 24 (9+9+6).
[ M(0) + m2(9) + m1(24) ] / [ M + m2 + m1 ] < 9
9m2 + 24m1 < 9(250) + 9m2 + 9m1
Notice that 9m2 cancels out on both sides.
15m1 < 2250
m1 < 150 g
This implies stability depends only on the upper mass being light enough. The lower mass m2 can be anything. (Validates statement d)
A “sluggish” response means a low frequency of oscillation. This happens when the Moment of Inertia (I) is high or the restoring torque is low.
Increasing the lower mass m2 adds mass at y=9. This increases the total inertia of the system. Additionally, mathematical analysis shows it raises the COM slightly towards the neutral point, reducing stability stiffness. Both factors slow down the oscillation.
Therefore, more mass in the lower ball makes the toy more sluggish. (Validates statement b)
