RBD O24

Solution Q24

Solution: Question 24

Diagram: Second Collision

CM_A CM_B Tip A Tip B 2nd Collision v = -u v = u
Step 1: Motion after First Collision

The Centers of Mass (CM) of both dumbbells are stationary. Both are rotating clockwise with angular velocity \( \omega = 2u/l \).
The “outer” particles (which didn’t collide initially) rotate in circles of radius \( l/2 \).

Step 2: Second Collision

After a rotation of \( \pi \) radians (half a circle), the top tip of Dumbbell A reaches the bottom point (the center line). Simultaneously, the bottom tip of Dumbbell B reaches the top point (the center line).
Thus, the two tips collide at the exact same location where the first collision occurred. This is the second collision.

Step 3: Outcome of Second Collision

Just before the second collision:
– Tip of A is moving Left with velocity \( -u \).
– Tip of B is moving Right with velocity \( +u \).
After elastic collision (velocity exchange):
– Tip of A acquires \( +u \).
– Tip of B acquires \( -u \).

Resulting Motion:
For Dumbbell A, both particles now move Right with velocity \( u \). Rotation stops, translation resumes.
For Dumbbell B, both particles move Left.
The dumbbells move away from each other and never return.

Conclusion: There is 1 initial collision and 1 subsequent collision.
Total Collisions = 2. Option (b).