KINEMATICS BYU 24

Solution – Question 24

Traffic Density Measurement

1. Identify Relative Velocities
Let the linear traffic density (vehicles per km) be $\lambda$.
Speed of vehicles, $v = 40$ km/h.
Speed of sensor, $u = 5$ km/h (moving opposite to traffic).

Sensor u = 5 km/h Traffic v = 40 km/h Scanning Length L

2. Flux Calculation
The sensor measures a length $L = 1$ km. The time taken for the sensor to cover this length is $t = L/u$.
During this time, the number of vehicles $N$ encountered is determined by the relative velocity between the sensor and the traffic. $$ v_{rel} = v + u = 40 + 5 = 45 \text{ km/h} $$ The rate at which vehicles pass the sensor (flux) is $R = \lambda v_{rel}$.
Total count $N = R \cdot t$.

Substituting the expressions:

$$ N = \lambda (v+u) \times \frac{L}{u} $$

3. Solving for Density ($\lambda$)
Rearranging for $\lambda$:

$$ \lambda = \frac{N u}{L(v+u)} $$ $$ \lambda = \frac{360 \times 5}{1 \times (40 + 5)} = \frac{1800}{45} = 40 \text{ vehicles/km} $$

4. Calculate for Specific Length
The question asks for the number of vehicles in a length $l = 100 \text{ m} = 0.1 \text{ km}$.

$$ n = \lambda \cdot l = 40 \times 0.1 = 4 $$

Answer: 4 vehicles