Solution: Period of Disc Oscillation
Step 1: Identifying the Energy Components
The system consists of a mechanical oscillator (mass on a spring) and an electrical component due to the motion of the conductor in the magnetic field. When the conducting disc moves with velocity $v$ in a magnetic field $B$, an electric field $E$ is induced inside the conductor due to charge separation (polarization).
The induced electric field is given by magnitude $E = vB$.
Step 2: Energy Stored in the Electric Field
Since the disc acts as a dielectric (in the sense of permitting field formation) or simply considering the energy density of the induced electric field in the volume $V$ of the disc:
Energy density $u_E = \frac{1}{2}\varepsilon_0 E^2$.
Total electrical energy $U_E = \text{Volume} \times u_E = V \left( \frac{1}{2}\varepsilon_0 (vB)^2 \right) = \frac{1}{2} (\varepsilon_0 V B^2) v^2$.
Step 3: Effective Mass and Period
The total energy of the system is the sum of kinetic energy (mechanical + electrical) and potential energy (spring).
$$ E_{total} = \frac{1}{2}mv^2 + \frac{1}{2}(\varepsilon_0 V B^2)v^2 + \frac{1}{2}kx^2 $$ $$ E_{total} = \frac{1}{2}(m + \varepsilon_0 V B^2)v^2 + \frac{1}{2}kx^2 $$This equation resembles the energy of a simple harmonic oscillator with an effective mass $m_{eff} = m + \varepsilon_0 V B^2$.
The period of oscillation for a spring-mass system is $T = 2\pi \sqrt{\frac{m_{eff}}{k}}$.
