ELECTROSTATICS O8

Solution 8

Solution

Plane A (+σ) Plane B (-σ) Resultant Field is Uniform (Parallel Lines)

Let’s determine the direction of the electric field in each quadrant. The field due to an infinite plane is uniform (constant magnitude and direction).

  • Plane A (+σ): Field points away from the plane (Left in Q2/Q3, Right in Q1/Q4).
  • Plane B (-σ): Field points towards the plane (Down in Q1/Q2, Up in Q3/Q4).

Vector Summation:

  • Q1 (Top-Right): Right + Down = $\searrow$ (South-East)
  • Q2 (Top-Left): Left + Down = $\swarrow$ (South-West)
  • Q3 (Bottom-Left): Left + Up = $\nwarrow$ (North-West)
  • Q4 (Bottom-Right): Right + Up = $\nearrow$ (North-East)

Why Option (b) is correct and (a) is incorrect:

Since the individual fields are uniform, their resultant must also be uniform in each quadrant. This implies the field lines must be straight, parallel, and equally spaced.

  • Option (b) correctly depicts these parallel, uniform field lines forming a “diamond” shape flow.
  • Option (a) is incorrect because it depicts a non-uniform field, contradicting the properties of infinite charged planes.

Answer: (b)