Solution to Question 22
Problem Statement: Determine the graph of frictional force $F$ between the block and plank versus time $t$.
Analysis:
The motion occurs in two distinct phases:
Phase 1: Relative Sliding
- Initially, the block slides over the plank. The friction is kinetic.
- Magnitude: $F = \mu_k mg = \text{constant}$.
- Graph Feature: A horizontal line parallel to the time axis.
Phase 2: Combined Motion (Sticking)
- Once the plank accelerates and the block decelerates enough, they reach a common velocity $v$. Relative motion stops.
- Now, the friction becomes static. It provides the force necessary to decelerate the block together with the plank.
- The external force on the system is drag on the plank: $F_{drag} = -kv$.
- System deceleration: $a = \frac{kv}{M+m}$.
- Required static friction on the block: $f_s = ma = \frac{mkv}{M+m}$.
Comparing Magnitudes:
- Kinetic friction $f_k$ was strong enough to accelerate the plank ($f_k > kv$).
- Static friction required is only a fraction of the drag force: $f_s = \frac{m}{M+m}(kv)$.
- Therefore, $f_s < f_k$. At the moment sticking occurs, the friction force drops suddenly.
- As time goes on, velocity $v$ decreases due to drag, so $f_s$ decreases proportionally.
Graph shape: Constant level $\rightarrow$ Sudden Drop $\rightarrow$ Decay to zero.
Correct Option: (d)
